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An electric bulb marked 40W-200V is used in a circuit of supply voltage 100V. Now its power is:

User Beingnin
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1 Answer

5 votes

Answer:

Power of the bulb is 10 Watts.

Step-by-step explanation:

We have,

Power and voltage of electric bulb is 40 W and 200 V. Using this data we can find the resistance of the bulb.

Power,
P=(V^2)/(R)

R is resistance


R=(V^2)/(P)\\\\R=((200)^2)/(40)\\\\R=1000\ \Omega

The supplied voltage is 100 V.

Now power is given by :


P=(V^2)/(R)\\\\P=(100^2)/(1000)\\\\P=10\ W

So, now the power of the bulb is 10 Watts.

User Lugarini
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