Answer:
a.) 2K (s) + ZnCl2 (aq) ---> Zn (s) + 2KCl (aq)
C3H8 (g) + 10O (g) ---> 4H2O (l) + 3CO2 (g)
b.) ZnCl2 = aqueous particle; 1 mol; 136.286 g
O=gaseous particle; 10 mols; 160 g
c.) 4 (?)
4 (?)
d.) Precipitation reaction
Combustion reaction
e.) ZnCl2 is the limiting reactant
O is the limiting reactant
f.) K is the excess reactant
C3H8 is the excess reactant
g.) 1 mol
3 mols