147k views
5 votes
Which shows how to find the value of this expression when x = negative 2 and y = 5?

(3 x cubed y Superscript negative 2 Baseline) squared
StartFraction 3 squared (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction
StartFraction 3 (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction
StartFraction 3 squared (5 Superscript 6 Baseline) Over (negative 2) Superscript negative 4 Baseline EndFraction
StartFraction 3 Over (2) Superscript 6 Baseline 5 Superscript 4 Baseline EndFraction

User Touyets
by
6.0k points

2 Answers

4 votes

Answer:

A

Explanation:

I took the test on edge

User Grigory Entin
by
5.2k points
6 votes

Answer:

(A)
(3^2(-2)^6)/(5^(4))

Explanation:

Given the expression;


(3x^3y^(-2))^2

When x=-2, y=5

We have:


(3(-2)^3(5)^(-2))^2=3^2\cdot(-2)^6\cdot5^(-4)\\=(3^2\cdot(-2)^6)/(5^(4))

The correct option is A

StartFraction 3 squared (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction

User Adam K Dean
by
5.9k points