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your family goes to a restaurant for dinner. there are 6 people in your family. some order the chicken dinner for $14.80 and some order the steak for $17. if the total bill was $91, how many people ordered chicken and how many ordered steak?

User Potray
by
7.9k points

2 Answers

4 votes

Answer:

5 ordered chicken, and 1 ordered steak

Explanation:

let's make c the number that ordered the chicken, and s the number that ordered steak. we're going to make an equation to solve for it:

14.8 c + 17 s = 91

We are in a situation where if someone orders chicken, they cannot have also ordered steak, and vice versa. This means we can make c or s equal to (6 - s) or (6 - c) respectively.

I will choose to replace s with (6 - c)

14.8c + 17 (6 - c) = 91

simplify

14.8c - 17 c + 102 = 91

subtract 102 from both sides and simplify cs

-2.2c = -11

divide by -2.2

c =5

This means that 5 people ordered chicken, and 1 ordered steak, bringing the total to 14.8 * 5 + 17 * 1 = 74 + 17 = 91

If you do the math the other way (replacing c with (6-s), you get the same answers (c = 5, s = 1)

User Jxtps
by
8.2k points
1 vote
(14.80)(5) = 74

6-5 = 1

(17)(1) = 17

74 + 17 = 91

5 family members orders chicken, and only one orders steak.
User Ravindra Kumar
by
8.3k points
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