Answer:
![x=-1\\y=4](https://img.qammunity.org/2021/formulas/mathematics/high-school/8vuqsh14bvcwvfol1urpic86wjep5ctn8m.png)
Explanation:
![(5x+2y)/(3)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/w7tggmzglokttjwwnb28g4goirv1x5wpfe.png)
![(2x+y)/(2)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ie1ml6uttpz53gznufzggvhjp9dpr83sei.png)
Vamos a utilizar el método de sustitución. Vamos a despejar la segunda ecuación por alguna de las variables. Elegiré la y porque esta sola.
![(2x+y)/(2)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ie1ml6uttpz53gznufzggvhjp9dpr83sei.png)
Vamos a empezar por eliminar ese 2 del denominador. Para hacer esto, multiplicamos por 2 ambos lados de la ecuación.
![2x+y=1*2](https://img.qammunity.org/2021/formulas/mathematics/high-school/eetsemxx384onyoebs4jaarynghw0p0vp0.png)
![2x+y=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/1q3xy7wuw2m2hxou1pi5i9i5hmvsr67y60.png)
Como vamos a despejar la y, restamos 2x en ambos lados.
![y=2-2x](https://img.qammunity.org/2021/formulas/mathematics/high-school/wdi5uw3gx1vsij9gph5u8z5gyz8hm0k0pl.png)
Listo.
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Procedemos a reemplazar el valor de y en la primera ecuación.
![(5x+2y)/(3)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/w7tggmzglokttjwwnb28g4goirv1x5wpfe.png)
![(5x+2(2-2x))/(3)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ck2txydpbi2b14s4zm8naiztz9arczewz0.png)
![(5x+4-4x)/(3) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/x2sc0dyp1zozp12x2lcf3hxsppwi3ovifu.png)
Procedemos a operar términos semejantes.
![(x+4)/(3) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/8f9hbf1dhobpti9vepnivqovuhs238jz5o.png)
Nos deshacemos del 3 multiplicando.
![x+4=1*3\\x+4=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ax9f5tz5i0yfd8wyp24yt5jbkx9xxj0sm.png)
Restamos 4
![x=3-4\\x=-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/98u6pylurxysl0mfmfiebmey0f64p29ult.png)
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Una vez encontrado el valor de x, procedemos a reemplazar en cualquier ecuación para encontrar el valor de y. Usaré la segunda ecuación.
![(2x+y)/(2)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ie1ml6uttpz53gznufzggvhjp9dpr83sei.png)
![(2(-1)+y)/(2)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/gypz6ibcg3iouetd50egfcunq7jh5a94l3.png)
Procedemos a resolver;
![(-2+y)/(2) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ezo4q1dkpt9bu55lxbth5worejfe53syzu.png)
Multiplicamos por 2.
![-2+y=1*2](https://img.qammunity.org/2021/formulas/mathematics/high-school/j5lnuc8nfut6vg8jqmw4k3wuxo2xbozdzw.png)
![-2+y=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/37e6bezr2y7r58ybfq0fbpgx8i2h1ert97.png)
Sumamos 2
![y=2+2\\y=4](https://img.qammunity.org/2021/formulas/mathematics/high-school/shsxfb3bhkgik6u7uxhxnc44gsoww4o9wi.png)
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Para comprobar que los valores son correctos, reemplazamos ambos valores en cualquier ecuación y el resultado debe ser igual.
Usaré la primera.
![(5x+2y)/(3) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ym37seu86m5l1jhdoy4mg8qanvvyzlp7of.png)
![(5(-1)+2(4))/(3) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/7ibo173vi4jui0ru9uaqntiejlcgc19yyx.png)
Resolvemos;
![(-5+8)/(3) =1](https://img.qammunity.org/2021/formulas/mathematics/high-school/1xc65m33swds26emuwoezo86tr4bh0chla.png)
![(3)/(3)=1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/10mx9onbzbtc7ncicfcmt47co5splxlzha.png)
![1=1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fb1lcpgd8poroiv1n3y8ulp3jy7jji8icz.png)