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Given: JL-tangent, LE-secant Prove: LU·LE = LV·LK
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Given: JL-tangent, LE-secant

Prove: LU·LE = LV·LK

Given: JL-tangent, LE-secant Prove: LU·LE = LV·LK-example-1
User Hussic
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Step-by-step explanation:

By the properties of secants and tangents, ...

LU·LE = LJ²

LV·LK = LJ²

By the transitive property of equality, ...

LU·LE = LJ² = LV·LK

LU·LE = LV·LK

User Updater XD
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