Question

How many moles of oxygen gas are there in 395 L of oxygen at STP?

Answer 1

17.6 moles of oxygen gas.

Step-by-step explanation:

STP Variables:

P=1 atm

R=0.082

T=273 K

Use the PV=nRT, then plug in.

n=PV/RT

n= (1 atm)(395 L)/(0.082) (273 K)

Simplify.

n=17.6 moles of O2

Hoped this helped.