Question

What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity of 5.0 × 106 m/s?

Answer 1

B. 1.0 x 10^-3

Step-by-step explanation:

Answer 2

The force exerted on a moving charge is
`1.02* 10^(-3)\ N`.

Step-by-step explanation:

We have,

Charge,
`q=-2\ \mu C`

Magnetic field,
`B=3* 10^(-4)\ T`

Velocity of charged particle,
`v=5* 10^6\ m/s`

Angle through the magnetic field,
`\theta=20^(\circ)`

It is required to find the force exerted on a moving charge. Due to the motion in charge, magnetic force acts on it. It can be given by :

`F=qvB\sin\theta`

Plugging all values above

`F=-2* 10^(-6)* 5* 10^6* 3* 10^(-4)* \sin (20)\\\\F=1.02* 10^(-3)\ N`

So, force exerted on a moving charge is
`1.02* 10^(-3)\ N`.