Question

I need help with this ( look at the picture I put)

Answer 1

12 H, 18 O, 6 C

Step-by-step explanation:

`6H_(2) O + 6CO_(2) -- > C_(6)H_(12) + 6O_(2)\\`

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first, we'll fo the h on the first equation:
`6H_(2)`

multiply the 6 and 2 to get twelve.

in the second equation, we see that there is
`H_(12)`

so, in both there are 12 H.

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Now we'll do O.

in the first equation we have
`6O + 6O_(2)`

so we have 6 + (6*2) or 6 + 12, which gives us 18

in the second equation we have
`O_(6) + 6O_(2)`

it's basically the same thing, just written differently, so we have 18.

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Finally, C.

In the first equation, we have
`6C`

in the second
`C_(6)`, again, same thing expressed differently.

both have 6 C.