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Meg has $4 more than loc. Pat has twice as much as meg and loc combined. Let d= loc’s nomber of dollars then when is mega and pats number of dollars

User Jpetazzo
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Answer:

Meg has $4 more than loc. Pat has twice as much as meg and loc combined. Let d= loc’s nomber of dollars then when is mega and pats number of dollars

User Amir Dadkhah
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3 votes

Answer:

Meg has (4 + d) dollars

Pat has (2m + 2d) dollars

Explanation:

Let d represents Loc's money

Let m represents Meg's money

Let p represents Pat's money

We are given that Meg has $4 more than loc

Mathematically,

m = 4 + d

Therefore, Meg has (4 + d) dollars

We are also given that Pat has twice as much as meg and loc combined

Mathematically,

p = 2*(m + d)

p = 2m + 2d

Therefore, Pat has (2m + 2d) dollars

Note: We have 2 equations and 3 unknowns therefore, we cannot have a unique solution to this problem.

User Jhonnatan
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