Question

) The dissociation energy (from the zero-point level) of ground-state O2 is 5.09 eV. There exists an electronically excited state of O2 whose zero-point level lies 6.21 eV above the zero-point level of the ground state. The ground-state molecule dissociates into two ground state O atoms, while the excited state of O2 dissociates into one O and one O* (electronically excited) atom. O* lies 1.97 eV above O. Sketch the potential energy curves and calculate the dissoc

Answer 1

Check the explanation

Step-by-step explanation:

Taking a look at the image, I have shown only the energy levels and not the proper curves, because we just need to calculate the energy differences.

Here, S2 denotes a ground state molecule while S2* denotes an excited state molecule

The energy D1, required for dissociation of excited state molecule to 2 ground state atoms is -ve, which means no energy is supplied, rather energy is emitted by this spontaneous dissociation.