Question

1) AU (C - B) =

2) AU (BNC)

3) AUBUC

4) B'N(A-C)

5) (BNC) - A -

6) C-(AUB) =

7) A'n (Bnc) -

8) ANBNC =

9) CU (ANB) =

10) (AUC)'UB -

Answer 1

`A \cup (C-B) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) = (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C`

Explanation:

`A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = B^c \cap (A \cap C^c) = (B^c \cap C^c) \cap A = (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C \cap A^c )\cap B^c = (C - A )\cap B\\`

`A^c \cap (B \cap C) = ( A^c \cap B) \cap C`