Answer:
On that Tuesday, there were 2 chefs and 13 customers at the restaurant.
Explanation:
Complete Question
Each chef at "sushi emperor" prepares 15 regular rolls and 20 vegetarian rolls daily. On Tuesday, each customer ate 2 regular rolls & 3 vegetarian rolls. by the end of the day, 4 regular rolls & 1 vegetarian roll remained uneating. How many chefs were on tuesday? and how many customers were they?
Solution
First of, let the number of chefs available at the restaurant on that fateful Tuesday be x
And the number of customers that came to eat at the restaurant on that fateful Tuesday be y
Each chef at "sushi emperor" prepares 15 regular rolls and 20 vegetarian rolls daily. Hence,
Total number of regular rolls made by a total of x chefs on that Tuesday = 15x
and the total number of vegetarian rolls made by x chefs on that Tuesday = 20x
On that Tuesday, each customer ate 2 regular rolls & 3 vegetarian rolls.
Total number of regular rolls ate by y customers = 2y
Total number of vegetarian rolls ate by y customers = 3y
The amount of each food left is then given as
4 regular rolls & 1 vegetarian roll remained uneating.
Note that; the number of food remaining is given as
(The number of food made by the chefs) - (The number of food eaten by the customers)
For regular rolls,
The number of food made by the chefs = 15x
The number of food eaten by the customers = 2y
The number of food remaining = 4
15x - 2y = 4 (eqn 1)
For vegetarian rolls,
The number of food made by the chefs = 20x
The number of food eaten by the customers = 3y
The number of food remaining = 1
20x - 3y = 1 (eqn 2)
Bringing eqn 1 and 2 together, we have
15x - 2y = 4
20x - 3y = 1
solving the simultaneous equations give a solution of x = 2 and y = 13.
Hence, on that Tuesday, there were 2 chefs and 13 customers at the restaurant.
Hope this Helps!!!