Question

2. If 0.544 moles of copper react with oxygen to form copper (I) oxide, how many grams of oxygen will be

consumed? You must start with a balanced chemical equation

Answer 1

4.352 grams of oxygen will be consumed.

Step-by-step explanation:

First of all you should bear in mind that the balanced chemical equation is:

4 Cu + O₂ → 2 Cu₂O

Then you can apply a rule of three as follows: if 4 moles of copper react with 1 mole of oxygen by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), 0.544 moles of copper with how many moles of oxygen do they react?

`moles of oxygen=(0.544 moles of copper* 1 mole of oxygen)/(4 moles of copper)`

moles of oxygen= 0.136

On the other hand, the molar mass of oxygen O2 is 32 g / mol (the mass of an oxygen being 16 g / mol). Then the mass that will be consumed is calculated using a rule of three: if 1 mole of oxygen has 32 g, 0.136 moles how much mass does it have?

`mass=(0.136moles*32 g)/(1mole)`

mass= 4.352 g

4.352 grams of oxygen will be consumed.