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4.00 L of a gas at standard temperature and pressure is compressed to 346 mL. What is the new pressure of the gas?

2 Answers

4 votes

Answer:

4005

Step-by-step explanation:

User Dakadaka
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2 votes

Ok I am not so sure about this one because I am new to learning the combined gas law but I think this is how you do it. So to solve this I would use the combined gas law which is:


(P_(1)V_(1) )/(T_(1) )=
(P_(2)V_(2) )/(T_(2) )

The 1 and 2 are the variable before and after they are compressed

P is the pressure in atm

V is the volume in L

T is the temperature in Kelvin

So first you need you to plug in all of the numbers in the variables.

Side note: standard temp is 273 Kelvin and standard pressure is 1 atm, also I converted the mL to L by dividing by 1000

(1)(4)/(divided by)/273K = P(0.346L)/(divided by)/273K then simplified its:

0.015 = 0.0013P then divide both sides by 0.0013

Which makes P=11.54

( I rounded most of my answers so it could be a bit different )

User Bob Fincheimer
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5.1k points