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Estimate the indicated probability by using the normal distribution as an approximation to the binomial distribution. A product is manufactured in batches of 120 and the overall rate of defects is 5%. Estimate the probability that a randomly selected batch contains more than 6 defects.

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4 votes

Answer:

41.68% probability that a randomly selected batch contains more than 6 defects.

Explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:


E(X) = np

The standard deviation of the binomial distribution is:


√(V(X)) = √(np(1-p))

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that
\mu = E(X),
\sigma = √(V(X)).

In this problem, we have that:


n = 120, p = 0.05

So


\mu = E(X) = np = 120*0.05 = 6


\sigma = √(V(X)) = √(np(1-p)) = √(120*0.05*0.95) = 2.39

Estimate the probability that a randomly selected batch contains more than 6 defects.

Using continuity correction, this is P(X > 6 + 0.5) = P(X > 6.5), which is 1 subtracted by the pvalue of Z when X = 6.5. So


Z = (X - \mu)/(\sigma)


Z = (6.5 - 6)/(2.39)


Z = 0.21


Z = 0.21 has a pvalue of 0.5832

1 - 0.5832 = 0.4168

41.68% probability that a randomly selected batch contains more than 6 defects.

User MrRobot
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