Question

How many moles are in 325mL of 1.25M (NH4)2SO4

Answer 1

`n_(solute)=0.406mol(NH_4)_2SO_4`

Step-by-step explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

`M=(n_(solute))/(V_(solution))`

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

`n_(solute)=M*V_(solution)=1.25(mol)/(L)*325mL*(1L)/(1000mL) \\\\n_(solute)=0.406mol(NH_4)_2SO_4`

Best regards.