Answer:
A) $18.36
B) $10.24
Step-by-step explanation:
Heat supplied Q = 24000 kJ/h
J/s = watt
I hour = 3600 sec, therefore 24000 kJ/hr becomes 24000/3600 = 6.67 kW
Coefficient of performance of heating for heat pump is
COP = T2/(T2 - T1)
T2 (hot temperature) = 20 °C
T1 (cold temperature) = -7 °C
COP = 20/(20 - (-7)) = 20/27 = 0.741
Also COP = Q/W
where W is the power input to the heat pump
0.741 = 6.67/W
W = 9 kW
Operating for one day is 24 hr
Therefore heat pump uses 9 x 24 = 216 kWh
Cost per day = ¢8.5 x 216 = ¢1836 = $18.36
For ground at 5°C
COP = 20/(20-5) = 20/15 = 1.33
1.33 = 6.67/W
W = 5.02 kW
For 24 hr it becomes 24 x 5.02 = 120.48 kWh
Cost = 8.5 x 120.48 = ¢1024.08 = $10.24