Question

The are six cards in box. 2 of them are blue and 4 are red. You randomly draw one card.

Find the probability of
a) Selecting a blue card
b) selecting a red card
c) which color card has a higher chance of being selected?

Answer 1

Explanation:

Answer 2

Given Information:

Number of blue cards = 2

Number of red cards = 4

Total number of cards = 6

Required Information:

a) P(Blue) = ?

b) P(Red) = ?

c) which color card has a higher chance of being selected?

Answer:

a) P(Blue) = 1/3

b) P(Red) = 2/3

c) Red card has a higher chance of being selected as compared to Blue card.

Step-by-step explanation:

We know that probability is given by

`P(x) = (Number \:of\: desired \:outcomes)/(Total\: number \:of\: outcomes)`

a)

The probability of selecting a Blue card is,

`P(Blue) = (Number \:of\: Blue \:cards)/(Total \:number \:of\: cards)\\\\P(Blue) = (2)/(6)\\\\P(Blue) = (1)/(3)`

b)

The probability of selecting a Red card is,

`P(Red) = (Number \:of\: Red \:cards)/(Total \:number \:of\: cards)\\\\P(Red) = (4)/(6)\\\\P(Red) = (2)/(3)`

c)

The probability of selecting a Red card is greater (2/3) as compared to Blue card (1/3) therefore, Red card has a higher chance of being selected as compared to Blue card.