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Find an equation of the parabola with vertex (5,4) and directrix y=9

User Kyle Baker
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1 Answer

4 votes

Answer:
(x-5)^2=-20(y-4)

Explanation:

Given

Vertex of parabola is
(5,4)

and directrix is
y=9

as directrix is above vertex so it downward facing parabola

Distance between directrix and parabola is


\mid 9-4\mid=5

so value of
a=5

Equation of parabola is


(x-5)^2=-4a(y-4)


(x-5)^2=-4(5)(y-4)


(x-5)^2=-20(y-4)

Find an equation of the parabola with vertex (5,4) and directrix y=9-example-1
User Abhay Saraf
by
5.2k points