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Find the values of x in the isosceles triangle

Find the values of x in the isosceles triangle-example-1

1 Answer

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Answer:

x = sqrt(55)

x = 7.416198487

Explanation:

We can use the Pythagorean theorem

The base is 3 (1/2 of 6). The other leg is x and the hypotenuse is 8

a^2 + b^2 = c^2

3^2 + x^2 = 8^2

9 + x^2 = 64

Subtract 9 from each side

9-9 +x^2 = 64-9

x^2 = 56

Take the square root of each side

sqrt(x^2) = sqrt(55)

x = sqrt(55)

x = 7.416198487

User Bkillnest
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