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A 1000-mL container of D-5-W contains 75 mEq KCI. The patient has received 575 mL of the fluids when they are discontinued. How many mEq has the patient received?

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Answer:

A = 43.13 meq

the patient received 43.13 meq of KCL

Explanation:

Given;

Total volume of container V = 1000 mL

KCL Content m = 75 meq

Concentration of KCL in the container volume is;

c = m/V

Substituting values;

c = 75/1000 meq/mL

c = 0.075 meq/mL

The amount A in meq of KCL in the fluid received by the patient;

The patient have received 575 mL

Amount A = concentration × volume

A = 0.075 meq/mL × 575 mL

A = 43.125 meq

A = 43.13 meq

the patient received 43.13 meq of KCL

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