Question

To what temperature will a 50.0 g piece of glass raise if it adsorbs 3275 J of heat

and its specific heat capacity is 0.50 J/gºC? The initial temperature of the glass is
15.0°C. Round to 4 significant figures. *

Answer 1

146.0 degrees C

Step-by-step explanation:

To answer this question, use the equation q = mcΔT

q = heat absorbed (J)

m = mass (g)

c = specific heat capacity (J/g*C)

delta T = change in temp in degrees C (final temp - initial temp)

We know the mass, the specific heat capacity, the heat, and the initial temp. Let's solve for the final temp (T)

3275 J = 50 g x 0.50 J/g*C x (T - 15 C)

3275 J = 25 J/C x (T - 15 C)

131 C = T - 15 C

146.0 C = T (temp final)