Answer:
(a) The amount of medication in the dog’s bloodstream 1 week is 2 ml.
(b) The amount of medication in the dog’s bloodstream 2 weeks is 1 ml.
(c) The amount of medication in the dog’s bloodstream 3 weeks is 0.50 ml.
Explanation:
The decay function is:

Here,
y = final amount
a = initial amount
r = decay rate
t = time
The function representing the number of ml of medicine left after w weeks, when a dog receives 4 ml of medication is:

(a)
Compute the amount of medication in the dog’s bloodstream 1 week as follows:

Thus, the amount of medication in the dog’s bloodstream 1 week is 2 ml.
(b)
Compute the amount of medication in the dog’s bloodstream 2 weeks as follows:

Thus, the amount of medication in the dog’s bloodstream 2 weeks is 1 ml.
(c)
Compute the amount of medication in the dog’s bloodstream 3 weeks as follows:

Thus, the amount of medication in the dog’s bloodstream 3 weeks is 0.50 ml.