Answer:
x = 7, x =
![(-1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ucdzi0lb0ex85q0y4vxwb9utyatoi4ifoi.png)
Explanation:
A restriction can only be found in the denominators and this is when x is a certain number that when plugged in, makes the expression 0 (this makes it undefined, which you cannot have).
Since we are only looking at the denominator, you can just ignore the numerator:
(x - 7) (5x + 1)
To find the restrictions, you must set them equal to 0:
x - 7 = 0
5x + 1 = 0
Then, solve:
x - 7 = 0 5x + 1 = 0
+ 7 + 7 - 1 - 1
________ ________
x = 7 5x = -1
x =
![(-1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ucdzi0lb0ex85q0y4vxwb9utyatoi4ifoi.png)
If you plug these numbers in, the total outcome would come out to be 0, making the expression undefined, proving that these are the restrictions of the expression.