Question

1). What is the theoretical yield of sodium oxide (Na₂O) in grams when 20.0g of calcium oxide (CaO) reacts with an excess amount of Sodium chloride?

2). How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃?
3). How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃?
4). Burning a candle is a combustion reaction that uses wax and oxygen to produce carbon dioxide, water, and energy. When you place a glass over a candle and the flame goes out, the limiting reactant is
5). If 15 g of C₂H₆ reacts with 60.0 g of O₂, how many moles of water (H₂O) will be produced? (Hint: use what you know about limiting reactant)
6). A reaction starts with 20.0 grams of lithium hydroxide (LiOH) and produces 31.0 grams of lithium chloride (LiCl), what is the percent yield of lithium chloride (LiCl)?
7). In the following reaction 6.13g of water (H₂O) is produced the theoretical yield of water (H₂O) is 8.17g, what is the percent yield of water?
8). If 8 moles of FeCl₃ react with 8 moles of O₂ what is the limiting reactant?

Answer 1

3. 52.5 mol O2

5. 1.5 mol H20

Step-by-step explanation:

hope it helps sorry for that, I dont rly know the others

Answer 2

1) 22.1 g Na₂O

Step-by-step explanation:

1) Writing out the balanced chemical equation is super important! The one for this problem is:

CaO + 2Na ⇒ Na₂O + Ca

Convert the grams of CaO to moles using the molar mass of CaO.

20 g CaO * (1 mole / 56.078 g) = 0.3566 moles of CaO

Now we can use the moles of CaO to find out how many moles of Na₂O will be produced. From the chemical equation written above, we can see that one mole of CaO will react to produce one mole of Na₂O.

So, 0.3566 moles of Na₂O will be produced

Convert the moles of Na₂O to grams using the molar mass:

0.3566 moles * (61.98 g / 1 mole) = 22.1 g Na₂O