Question

What is the center of the circle?
(x + 1)2 + (y – 12 = 256

Answer 1

The equation of circle:

`(x-x_0)^2+(y-y_0)^2=r^2`

`(x + 1)^2 + (y - 1)^2 = 256`

so, the center of the circle is (-1; 1)