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What is the center of the circle?
(x + 1)2 + (y – 12 = 256

User Niquan
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1 Answer

4 votes

The equation of circle:


(x-x_0)^2+(y-y_0)^2=r^2


(x + 1)^2 + (y - 1)^2 = 256

so, the center of the circle is (-1; 1)

User Alexandros
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