Question

In rabbits, black fur is dominant over white fur. Show the cross of a heterozygous black male with a homozygous white female.

Key:
Parents & Gametes:
Genotype Ratio:
Phenotype Ratio:

Answer 1

Parents & Gametes: Bb × bb

Genotype Ratio: 1Bb:1bb

Phenotype Ratio: 1black fur: 1white fur

Step-by-step explanation:

This is a monohybrid cross involving a single gene coding for fur colour in rabbits. The allele for black fur (B) is dominant over the allele for white fur (b).

In a cross between heterozygous black male with a homozygous white female, a heterozygous black male will possess genotype: Bb while a homozygous white female will possess genotype: bb

Hence, using a punnet square, the following gametes will be produced by each parent as follows:

Bb- B and b

bb- b and b

The genotypic ratio based on the punnet square is 1Bb : 1bb

The phenotypic ratio is 1 black : 1 white fur rabbit