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Find the radius of the circle defined by the equation x ^ 2 + y ^ 2 = 121 .

User Vladan
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Answer: The radius is 11(14−3)and the coordinates of the centre is (7,3)

Step-by-step explanation:Opening up the equation,(x+7)2+(y−3)2=121

x2+14

x+49+y2−6

y+9=121

y2−6

y=63−x2+14

Find the x-intercepts, and the midpoint to find x-line of symmetry,

When y=0,x2 −14

x − 63 = 0

x = 17.58300524 or x = −3.58300524

17.58300524 −3.58300524

2=7

Find the highest and lowest point and midpoint,

When x=7,y2−6

y−112 = 0

y=14 or y=−8

14−8/2=3

Hence, the radius is 11(14−3)and the coordinates of the centre is (7,3)

User Deepwinter
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