Question

4x + 3y ≤ 15 (solve for Y)

Answer 1

`\huge \boxed{y \leq (-4x+15)/(3) }`

`\rule[225]{225}{2}`

Explanation:

`4x + 3y \leq 15`

Subtracting 4x from both sides.

`3y \leq 15-4x`

Dividing both sides by 3.

`\displaystyle y \leq (15-4x)/(3)`

`\rule[225]{225}{2}`

Answer 2

y≤15/3-4/3x

Explanation:

4x+3y≤15

3y≤15-4x

y≤15/3-4/3x