Question

A reaction of 12.640g of copper oxide with 0.316 g hydrogen produces 2.844 g of water Xg of copper X=__ g

Answer 1

it’s 10.112

Step-by-step explanation:

Answer 2

`m_(Cu)=10.04gCu`

Step-by-step explanation:

Hello,

In this case, the undergoing chemical reaction is:

`CuO+H_2\rightarrow H_2O+Cu`

Now, since 2.844 g of water are produced, one could compute the grams of copper considering the produced water via stoichiometry and their 1:1 molar ratio:

`m_(Cu)=2.844gH_2O*(1molH_2O)/(18gH_2O)*(1molCu)/(1molH_2O)*(63.546 g Cu)/(1molCu)\\ \\m_(Cu)=10.04gCu`

Best regards.