Question

How much ice at 0°C could be melted by the addition of 15 kJ of heat? (ΔHfus = 6.01 kJ/mol)

a. 0.4 g

b. 2.5 g

c. 7.2 g

d. 45 g

Answer 1

d. 45 g

Step-by-step explanation:

The amount of ice melted is:

`\Delta n = (15\,kJ)/(6.01\,(kJ)/(mol) )`

`\Delta n = 2.496\,moles`

`\Delta m = \Delta n \cdot M_w`

`\Delta m = (2.496\,moles)\cdot \left(18\,(g)/(mol) \right)`

`\Delta m = 44.928\,g`

Answer 2

Answer: d.45 g

Explanation:see attached photo