Write the equation of the line perpendicular to 2x - 3y = 1 that passes through the point (3,-5) in slope-intercept form and in standard form.

Question

asked Dec 1, 2021 161k views

2 Answers

Shibapoo · Answer 1 · 2021-12-02T20:52:06+0000

Answer:

y = -3/2x - 1

Explanation:

this line 2x-3y=9 can be rewritten as

y = 2/3x - 3

The slope of this line is 2/3

If two lines are perpendicular, then their slopes satisfy condition

m1 . m2 = -1

Thus, the slope of the needed line is

m = -3/2

The equation of the line passing through the point (2,-4) and perpendicular to the line 2x-3y=9 is

y + 4 = 3/2 (x - 2)

y = -3/2 x - 1