Answer:
option C: B = 0.48; b = 0.52
Step-by-step explanation:
Of the 50 mice, 12 were homozygous black (BB), 24 were heterozygous black (Bb), and 14 were brown (bb).
BB Bb bb Total
12 + 24 + 14 = 50
the formular for alleleic frequency (p) is (BB+ Bb/2) / total,
q = (bb + Bb/2) / total
Allelic frequecy of B (p) is (12 + 24/2) /50 = 12 + 12 = 24/50 = 0.48
Allelic frequency of b (q) is (14 + 24/2) / 50= 14 + 12 = 26/50 = 0.52
check p + q = 1; 0.48 + 0.52 = 1