Question

a 3.50L sample of neon gas has a pressure of .950atm at 20c what would the volume be if the pressure increased to 1.50atm and the temperature remained constant

Answer 1

`V_2=2.22L`

Step-by-step explanation:

Hello,

In this case, we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:

`P_1V_1=P_2V_2`

Thus, solving for the final volume, once the pressure changes, we obtain:

`V_2=(P_1V_1)/(P_2)=(3.50L*0.950atm)/(1.50atm) \\\\V_2=2.22L`

Best regards.