Question

If function g(x) = x2 + 2 is a transformation of the quadratic parent function, f(x) = x2, where is the y-intercept of function g located?

Answer 1

Explanation:

c

Answer 2

We have been given that function
`g(x)=x^2+2` is a transformation of the quadratic parent function
`f(x)=x^2`. We are asked to find the y-intercept of function g.

We know that the function
`f(x)=x^2` is an upward opening parabola with vertex at point (0,0).

We know that vertex form of a parabola is in form
`y=a(x-h)^2+k`, where point (h,k) represents vertex of parabola.

We can rewrite g(x) as:

`g(x)=(x-0)^2+2`

The vertex of the function g(x) is at point (0,2).

We know that the vertex of a function is the point, when x is equal to 0. Therefore, the y-intercept of the g is at (0,2).