Question

What are the possible values of x if (4x-5)2=49

Answer 1

3, -1/2

Explanation:

(4x-5)^2=49

Take the square root of each side

sqrt(4x-5)^2=±sqrt(49)

4x-5 = ±7

Add 5 to each side

4x-5+5 =5 ±7

4x = 5 ±7

Divide each side by 4

4x/4 = (5 ±7)/4

x = (5 ±7)/4

Solve for the positive

x =(5+7)/4 = 12/4 =3

Now the negative

x = (5-7)/2 = -2/4 = -1/2