Answer:
For this case we know that the confidence level is 90% so then the significance level is
and
. And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
![z_(\alpha/2)= \pm 1.645](https://img.qammunity.org/2021/formulas/mathematics/college/2xehsev7i2h7u9cmra5mrxc0ue7691gl70.png)
And the best option would be:
1.645
Explanation:
We assume that the parameter of interest is
and we can assume that the distribution for this parameter is normally distributed so then the confidence interval assuming a two sided interval is given by:
![\hat \theta \pm z_(\alpha/2) SE](https://img.qammunity.org/2021/formulas/mathematics/college/u5p9d2y5veg04o2mq60cm1l3h81d2tyve8.png)
Where
represent the estimator for the parameter, SE the standard error and
the critical value.
For this case we know that the confidence level is 90% so then the significance level is
and
. And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
![z_(\alpha/2)= \pm 1.645](https://img.qammunity.org/2021/formulas/mathematics/college/2xehsev7i2h7u9cmra5mrxc0ue7691gl70.png)
And the best option would be:
1.645