Question

1. What is the density of a sample of ammonia gas, NH, if the pressure is 0.928 atm and the temperature is 63 degrees

Celsius?

Answer 1

Answer : The density of a sample of ammonia gas is, 0.572 g/L

Explanation :

To calculate the density of ammonia gas we are using ideal gas equation.

`PV=nRT\\\\PV=(w)/(M)RT\\\\P=(w)/(V)(RT)/(M)\\\\P=(\rho RT)/(M)`

where,

P = pressure of ammonia gas = 0.928 atm

V = volume of ammonia gas

n = number of moles of ammonia gas

w = mass of ammonia gas

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of ammonia gas =
`63^oC=273+63=336K`

M = molar mass of ammonia gas = 17 g/mol

Now put all the given values in the above formula, we get:

`P=(\rho RT)/(M)`

`0.928atm=(\rho * (0.0821L.atm/mol.K)* (336K))/(17g/mol)`

`\rho=0.572g/L`

Therefore, the density of a sample of ammonia gas is, 0.572 g/L