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The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.3 cm pipes. (a) If the flow rates in the three smaller pipes are 27, 16, and 11 L/min, what is the flow rate in the 2.0 cm pipe? (b) What is the ratio of the speed of water in the 2.0 cm pipe to that in the pipe carrying 27 L/min?

User Umut Sirin
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1 Answer

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Answer:

a)54L/min

b)0.845

Step-by-step explanation:

a) A x V=
A_1V_1+ A_2V_2+A_3V_3

where suffix 1,2,3 refers to the three pipes.

=27L/min+16L/min+11 L/min

=54L/min

b) A x V=54L/min =>
(\pi )/(4) d^2 x v

d= 2 cm


(\pi )/(4) d^2 x v = 54

v=
(4)/(\pi ) x
(54)/(2^2)

->
A_1 x
V_1=27L/min =>
(\pi )/(4) d_1^2 x
v_1


d_1= 1.3cm


(\pi )/(4) d^2 x
v_1 = 27


v_1=
(4)/(\pi ) x
(27)/(1.3^2)

Next is to find the ratio of speed i.e
(v)/(v_1)


(4)/(\pi ) x
(54)/(2^2) /
(4)/(\pi ) x
(27)/(1.3^2) =>
(54)/(27)
(1.3^2)/(2^2)


(v)/(v_1)= 0.845

User Manuel Salvadores
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