Answer:
a)54L/min
b)0.845
Step-by-step explanation:
a) A x V=
![A_1V_1+ A_2V_2+A_3V_3](https://img.qammunity.org/2021/formulas/physics/college/sn0e7dgvqx8fjmqczmsbytnk6d5xwf1jlw.png)
where suffix 1,2,3 refers to the three pipes.
=27L/min+16L/min+11 L/min
=54L/min
b) A x V=54L/min =>
x v
d= 2 cm
x v = 54
v=
x
->
x
=27L/min =>
x
![v_1](https://img.qammunity.org/2021/formulas/physics/high-school/rlq1oizica164pcx8s5ic1b2qiicmivudt.png)
= 1.3cm
x
= 27
=
x
![(27)/(1.3^2)](https://img.qammunity.org/2021/formulas/physics/college/i6rzquq31yis5ssq6ggll7p3yw9xlkog3j.png)
Next is to find the ratio of speed i.e
![(v)/(v_1)](https://img.qammunity.org/2021/formulas/physics/college/bkggxvfbntzcuv0hdsk9pyuxg8y930o9ne.png)
x
/
x
=>
![(1.3^2)/(2^2)](https://img.qammunity.org/2021/formulas/physics/college/n6npe1py18z88jsx9w27hqevb68z5i3u0y.png)
= 0.845