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CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s).

Suppose this reaction takes place in a sealed container in which the gas occupies a volume of 1.50 liters. The container is kept at a temperature of 0°C. If 5.18 grams of calcium carbide reacts with excess water, what is the partial pressure of the ethyne gas produced, in atmospheres?

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Answer:

The partial pressure of the ethyne is 1.21 atmospheres.

Step-by-step explanation:

The molar mass of calcium carbide is 64.100 grams/mole. Convert the amount of calcium carbide from grams to moles:

5.18 g × = 0.0808 mol CaC2.

The ratio of calcium carbide to ethyne is 1 : 1, so 0.0808 mol of ethyne is produced.

Use the ideal gas law to find the pressure after converting the temperature to kelvins:

0°C + 273.15 = 273 K.

Now solve the ideal gas law formula for pressure:

PV = nRT

P =

The answer needs to be in atmospheres, so use

R = 0.0821 L atm/mol K:

P =

= 1.21 atm

User Samuel Gfeller
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