Answer:
The partial pressure of the ethyne is 1.21 atmospheres.
Step-by-step explanation:
The molar mass of calcium carbide is 64.100 grams/mole. Convert the amount of calcium carbide from grams to moles:
5.18 g × = 0.0808 mol CaC2.
The ratio of calcium carbide to ethyne is 1 : 1, so 0.0808 mol of ethyne is produced.
Use the ideal gas law to find the pressure after converting the temperature to kelvins:
0°C + 273.15 = 273 K.
Now solve the ideal gas law formula for pressure:
PV = nRT
P =
The answer needs to be in atmospheres, so use
R = 0.0821 L atm/mol K:
P =
= 1.21 atm