Answer:

Explanation:
Given:
- Volume of fuel = 5/6
- Volume of fuel used each time = 1/12
- Number of travels to or from work = x
Since each time 1/12 of the tank is used, and initial volume is 5/6 of the tank, the equation will be:
Solving the equation we get:
So Felitz can travel 10 times to/from work with 5/6 full tank