Question

a and b are vectors such that |a| = √3, |b| = 1, and the angle between them is 5π/6. Using scalar product, find the exact value of |2a + b|.

Answer 1

|2a + b| = 2√(3) + 1

Explanation:

|a| = √(3)

|b| = 1

θ = 5π/6

For scalar vectors, A.B = |a|.|b|.cosθ

a

|2a| = 2*√(3) = 2√(3)

|2a + b| = 2√(3) + 1

Since we don't have to find the scalar or dot product, there's no need to use the formula requiring the angle between them

|2a + b| = 2√(3) + 1