Question

What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.

Answer 1

Q = 31798.4J = 31.79kJ

Step-by-step explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ