Question

If a gas sample has a volume of 5 L at STP what would be its volume at 45C

Answer 1

`\large \boxed{\text{5.8 L}}`

Step-by-step explanation:

Data:

p₁ = 1 bar; V₁ = 5 L; T₁ = 0 °C

p₂ = 1 bar; V₂ = ?; T₂ = 45 °C

The pressure and the number of moles are constant, so, to calculate the volume, we can use Charles' Law.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Calculations:

(a) Convert temperatures to kelvins

T₁ = (0 + 273.15) K = 273.15 K

T₂ = (45 + 273.15) K = 318.15 K

(b) Calculate the new volume

`\begin{array}{rcl}(V_(1))/(T_(1)) &= &(V_(2))/(T_(2))\\\\(5)/(273.15) &= &(V_(2))/(318.15)\\\\0.018 &= &(V_(2))/(318.15)\\\\{ V_(2)} &=& 0.018 * 318.15\\&=& \textbf{5.8 L}\\\end{array}\\\text{The volume will be $\large \boxed{\textbf{5.8 L}}$}`