Answer:
![\boxed{\text{A1: 12.5 g/L ; A2: 133 g/L; B1: 20 \% by volume; B2: 6 mL}}](https://img.qammunity.org/2021/formulas/chemistry/high-school/51qomxfwjc2fdjykania9hskplyk1e05vz.png)
Step-by-step explanation:
A. Concentration
Question 1
![\begin{array}{rcl}\text{Concentration} & = & \frac{\text{Mass of solute}}{\text{Volume of solution}}\\\\& = & \frac{\text{25 g}}{\text{2 L}}\\\\& = &\textbf{12.5 g/L}\\\end{array}\\\text{The concentration of sugar is $\boxed{\textbf{12.5 g/L}}$}](https://img.qammunity.org/2021/formulas/chemistry/high-school/f92pr6zfgnxi7zxj9hjo9tdsnhhukiur3g.png)
Question 2
![\begin{array}{rcl}\text{Concentration} & = & \frac{\text{100 g}}{\text{0.750 L}}\\\\& = &\textbf{133 g/L}\\\end{array}\\\text{The concentration of the additive is $\boxed{\textbf{133 g/L}}$}](https://img.qammunity.org/2021/formulas/chemistry/high-school/nnr7k7ubcszy4ct2egpzq7iu3gy9wu7emv.png)
B. Percent by volume
Question 1
The formula for percent by volume is
![\text{Percent by volume} = \frac{\text{Volume of solute}}{\text{Volume of solution}}* 100 \, \%](https://img.qammunity.org/2021/formulas/chemistry/middle-school/gllf8c0bsa1716y4cezilmzvj2iqyjp40v.png)
If your solution contains 50 mL of rubbing alcohol and 200 mL of water, the volume of solution is 250 mL,
![\begin{array}{rcl}\\\text{Percent by volume} & = & \frac{\text{50 mL}}{\text{250 mL}}* 100 \, \%\\\\& = & 20 \, \%\\\end{array}\\\text{The concentration of the solution is $\large \boxed{\textbf{20 \% by volume}}$}](https://img.qammunity.org/2021/formulas/chemistry/high-school/vrtv86qgjvhptdm6hiuil6tcw3rjaz1dxx.png)
Question 2
If you have 300 mL of a solution that is 2 % v/v H₂O₂,
![\begin{array}{rcl}2 \, \% & = & \frac{\text{Volume of H$_(2)$O}_(2)}{\text{300 mL}}* 100 \, \%\\\\2 * \text{300 mL} & = & \text{Volume of H$_(2)$O}_(2) * 100\\\\\text{Volume of H$_(2)$O}_(2) & = & \frac{2 * 300\text{ mL}}{100}\\\\ & = & \textbf{6 mL}\\\end{array}\\\text{The volume of H$_(2)$O$_(2)$ in the solution is $\large \boxed{\textbf{6 mL}}$}](https://img.qammunity.org/2021/formulas/chemistry/high-school/pw9pxwaqyhgqrh06krxv99x82ndqkjqc5p.png)