Question

The percentage of nitrogen in urea (NH 2CONH 2 ​ ), is:​

Answer 1

Molecular mass of urea (NH 2CONH 2) × 2

× (Atomic mass of N ) + 4

× (Atomic mass of H) + (Atomic mass of C) + (Atomic mass of O) = 60

Mass percentage of N =

Total mass of N atoms in the compound / Mass of compound × 100 = 28 / 60 × 100 = 46.67

Step-by-step explanation:

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Answer 2

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