Question

How many liters of 4.0 M NaOH solution will react with 1.8 mol H2SO4? (Remember to balance the equation.

Answer 1

Stoichiometry and Solutions

When solving stoichiometry problems with solutions, there are some equations and concepts we must know:

• 
  `C=(n)/(V)`, where C = concentration, n = moles and V = volume

• With general stoichiometry, we always must write and balance a chemical equation. This can help us write mole ratios based on the coefficients of products/reactants.

Solving the Question

First, write and balance a chemical equation with NaOH and H2SO4:

`NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O\\2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O`

We're given:

• 
  `[NaOH]=4.0mol/L`
• 
  `n_(H_2SO_4)=1.8 mol`

Now, solve for moles of NaOH using a mole ratio:

`(n_(NaOH))/(2)=(n_(H_2SO_4))/(1)\\\\n_(NaOH)=1.8*2\\\\n_(NaOH)=3.6`

Therefore, the moles of NaOH is 3.6 moles.

Finally, solve for the volume of NaOH using
`C=(n)/(V)`:

`C=(n)/(V)`

`V=(n)/(C)\\\\V=(3.6)/(4.0)\\\\V=0.9`

Therefore, the volume of NaOH is 0.9 L.

Rounded to significant figures, this would be 0.90 L.

Answer

0.90 L