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The intensity of solar radiation at the top of the Earth's atmosphere is 1506 W/m^2. Assuming 60% of the incoming solar energy reaches the Earth's surface and you absorb 50% of the incident energy, find the amount of solar energy you absorb if you sunbathe for 58 minutes.

User Phorden
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Answer:

The correct answer to the following question will be "7.54 *10⁶ J".

Step-by-step explanation:

The given values are:

Earth's top intensity of solar radiation,


lo=1506 \ W/m^2

At the surface of the earth,


l1=(1506* 60)/(100)


=903.6 \ W/m^2

Now,


Absorbed \ by \ humans = (903.6* 50)/(100)


=451.8 \ W/m^2

As we know,


radiation \ intensity=(power)/(area)

and,


power=(energy)/(time)

So,

The amount of solar energy absorbed by us,


=451.8* 58* 60* 1.6* 0.3


=7.54* 10^6 \ J

User Robert Giesecke
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