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What is the mass of 0.175 moles of Fe2O2

What is the mass of 0.175 moles of Fe2O2-example-1
User Kmt
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1 Answer

1 vote

Answer:

27.9 grams of Fe2O3

Step-by-step explanation:


\frac{0.175 moles Fe2O3}{} *
(159.69 g Fe2O3)/(1 mole Fe2O3) =
(27.94575)/(1) = 27.9 grams

Looking at the model given, I simply found the molar mass of Fe2O3 so I can set up an equation to find the number of grams. The molar mass of Fe2O3 is 159.69 grams. Since we are given that there are 0.175 moles of Fe2O3, then we can use that first in our equation. As you can see, I used the conversion factor 159.69 grams Fe2O3 = 1 mole Fe2O3. By using this conversion factor, it was easy for me to set up an easy equation so I can find the number of grams of Fe2O3 when given 0.175 moles of Fe2O3.

After doing the math and following the rules of significant figures, you will end up with 27.9 grams Fe2O3 which is answer choice D

User Shiva Achari
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